9t^2-4t+1=5t^2

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Solution for 9t^2-4t+1=5t^2 equation: 



9t^2-4t+1=5t^2

We move all terms to the left:

9t^2-4t+1-(5t^2)=0

determiningTheFunctionDomain
9t^2-5t^2-4t+1=0

We add all the numbers together, and all the variables

4t^2-4t+1=0

a = 4; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{4}{8}=1/2$

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